… Outside any neighborhood of 0 the functional t>+/r(S + 1) acts like a finite measure, so that
we can actually apply t+/r(S + 1) to any continuous function that is infinitely differentiable on a …

… Tsirelson’s space T [LT, Example 2.e.1]. Recall that T is generated by a norm ·T on c00
satisfying … This forces the unit vectors in T to be not subsymmetric, unlike in X. The admissibility …

… Schlumprecht, On distorted norms in Banach spaces and the existence of ℓp types,
preprint. [11] RC James, Uniformly nonsquare Banach spaces, Ann. Math. … Schlumprecht …

… By a subtree of a tree T = (x(α))α∈Tk ∈ Tk(X) we mean a family T = (x(α))α∈T with T ⊂
Tk having the property that for any α ∈ (T ∩Tk−1)∪{∅} the set {n ∈ N : (α, n) ∈ …

… Every countably infinite countably branching tree T of a certain type on a space X is … T
is a topology on X (for example the weak topology), we call a tree T -null if every node is a T …

Let (e i ) be a fundamental system of a Banach space. We consider the problem of approximating
linear combinations of elements of this system by linear combinations using quantized …

We prove that a sequence (f i ) i=1 ∞ of translates of a fixed f ∈ L p (ℝ) cannot be an
unconditional basis of L p (ℝ) for any 1 ≤ p < ∞. In contrast to this, for every 2 < p < ∞, d ∈ ℕ and …

The Gaussian correlation conjecture states that for any two symmetric, convex sets in n-dimensional
space and for any centered, Gaussian measure on that space, the measure of the …

… androulakis and t. schlumprecht Concerning the invariant subspace problem, note that if
every strictly singular operator on GM has some compact power, then, by [6], GM will still be …

… by Ostrovskii [33] to embed l2 coarsely into every Banach space with an unconditional basis
and nontrivial cotype using the Mazur maps constructed by Odell and Schlumprecht in their …